You can print Pyramid pattern of stars or numbers using loops and print methods in Java. There are two print method you need to know, System.out.print() and System.out.println(), the difference between print() and println() is that println adds a new line character at the end i.e. it appends \n automatically. which means next time you write something will begin at the new line. On the other hand, if you use print() then the text is appended to the same line. By using these two methods, you can print any kind of pattern in Java program e.g. pattern involving multiple stars in one line, a pattern involving stars at different lines, pyramid of numbers, a pyramid of stars, inverted pyramid pattern of numbers, stars and alphabets, and so on.

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**Coding Interview Question**. Tampilkan semua postingan## Minggu, 16 Oktober 2016

## Rabu, 12 Oktober 2016

- Oktober 12, 2016
- EXCATION
- Coding Interview Question, data structure and algorithm
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Write a program to calculate the square root of a number in Java or C++ is one of the popular coding interview questions from Programming job interviews both on tech companies like Facebook, Amazon, and investment banks like Citibank and Bank Of America etc. The problem may look easy because you might know how to find the square root of a number but it's not. In fact, it's one of the tricky questions you would encounter in programming job interviews. The first hurdle is do you really remember how to calculate square root by hand? Many programmers don't. I know they have learned it past but when you ask them to calculate square root by hand, many won't remember the algorithm they have learned in school or college.

Read more �## Selasa, 04 Oktober 2016

- Oktober 04, 2016
- EXCATION
- Coding Interview Question, data structure and algorithm
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Can you write a

Read more �**Java program to check if two rectangles are overlapping with each other or not?**is one of the frequently asked coding questions on tech giants like Facebook, Amazon, Microsoft and others. This is also a kind of problem where it's easy to find opposite or negative conditions e.g.*when rectangles are not overlapping*and then inverting the result to prove that rectangles are colliding with each other. I first heard about this problem from one of my friend who was on Android game development space. He was asked to write an algorithm to find if given rectangles are intersecting or not. He was given the choice to implement the algorithm in any programming language e.g. Java, C, C++ or even pseudo code was fine, so don't worry about language here, it's more about algorithm and logic. He is a genius so he came successful from that interview, impressing the interviewer, talking about efficiency and accuracy of the algorithm as well.## Minggu, 31 Juli 2016

The problem to find the 3rd element from the end in a singly linked list or nth node from the tail is one of the tricky but frequently asked linked list problems in programming job interviews. The challenge here is to solve the problem in just one pass, i.e. you can not traverse the linked list again and you cannot traverse backward because it's a singly linked list. If you have practiced some linked list problems e.g. finding length, inserting elements, or deleting elements then you should be familiar with traversal. Here, we'll use the same algorithm which we have used to find the middle element of linked list in one pass. The algorithm is also known as

Read more �**tortoise and hare algorithm**because of the speed of two pointers used by the algorithm to traverse the singly linked list.## Minggu, 03 Juli 2016

- Juli 03, 2016
- EXCATION
- Coding Interview Question, core java
- No comments

One of the common programming questions is,

Read more �**how do you find the largest and smallest number in N numbers without using arrays in Java?**Can you write a program to solve this problem? Well, it's very similar to the problem we have seen before, find the largest and smallest of 3 integers. You can use the same approach and generalize it for N numbers. All you need to do is start with largest as Integer.MIN_VALUE and smallest number as Integer.MAX_VALUE and loop through N numbers. At each iteration, compare the number with the largest and smallest number, if the current number is larger than largest than its a new largest and if the current number is smaller than smallest than its a new smallest number.## Kamis, 09 Juni 2016

- Juni 09, 2016
- EXCATION
- Coding Interview Question, String
- No comments

This week's coding exercise is to

Read more �**remove duplicate characters from String in Java**. For example, if given String is "aaaaaa" then output should be "a", because rest of the "a" are duplicates. Similarly, if the input is "abcd" then output should also be "abcd" because there is no duplicate character in this String. By the way, you can not use any third-party library or Java API method to solve this problem, you need to develop your own logic or algorithm and then write code to implement that algorithm. This is one of the interesting problems from Java coding interviews and you can use this program to weed out Java programmers who cannot write code. This problem is much better than Fizzbuzz because it requires more logic and coding than solving Fizzbuzz.## Sabtu, 28 Mei 2016

- Mei 28, 2016
- EXCATION
- Coding Interview Question, core java
- No comments

You can reverse an ArrayList in place in Java by using the same algorithm we have used to reverse an array in place in Java. If you have already solved that problem then It's a no-brainer because ArrayList is nothing but a dynamic array, which can resize itself. All elements of an array are stored in the internal array itself. By the way, if you need to reverse an ArrayList then you should be using the Collections.reverse() method provided by Java Collection framework. It's generic method, so you can not only reverse an ArrayList but also Vector, LinkedList, CopyOnWriteArrayList, or any other List implementation. Though, worth noting is that this method internally uses a ListIterator for reversing the list, which might not be as efficient as our algorithm.

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